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Chapter 11 Practice MC Test: Testing a Claim



Multiple Choice
Identify the choice that best completes the statement or answers the question.
 

 1. 

DDT is an insecticide that accumulates up the food chain. Predator birds can be contaminated with quite high levels of the chemical by eating many lightly contaminated prey. One effect of DDT upon birds is to inhibit the production of the enzyme carbonic anhydrase, which controls calcium metabolism. It is believed that this causes eggshells to be thinner and weaker than normal and makes the eggs more prone to breakage. (This is one of the reasons why the condor in California is near extinction.) An experiment was conducted where 16 sparrow hawks were fed a mixture of 3 ppm dieldrin and 15 ppm DDT (a combination often found in contaminated prey). The first egg laid by each bird was measured, and the mean shell thickness was found to be 0.19 mm. A “normal” eggshell has a mean thickness of 0.2 mm.

The null and alternative hypotheses are
A)
mc001-1.jpg
B)
mc001-2.jpg
C)
mc001-3.jpg
D)
mc001-4.jpg
E)
mc001-5.jpg
 

 2. 

A significance test allows you to reject a hypothesis mc002-1.jpg in favor of an alternative Ha at the 5% level of significance.  What can you say about significance at the 1% level?
A)
mc002-2.jpg can be rejected at the 1% level of significance.
B)
There is insufficient evidence to reject mc002-3.jpg at the 1% level of significance.
C)
There is sufficient evidence to accept mc002-4.jpg at the 1% level of significance.
D)
Ha can be rejected at the 1% level of significance.
E)
The answer can’t be determined from the information given.
 

 3. 

In a test of H0: µ = 100 against Ha: µ mc003-1.jpg 100, a sample of size 80 produces z = 0.8 for the value of the test statistic. The P-value of the test is thus equal to
A)
0.20
B)
0.40
C)
0.29
D)
0.42
E)
0.21
 

 4. 

Which of the following is/are correct?
      I.      The power of a significance test depends on the alternative value of the parameter.
      II.      The probability of a Type II error is equal to the significance level of the test.
      III.      Type I and Type II errors make sense only when a significance level has been chosen in advance.
A)
I and II only
B)
I and III only
C)
II and III only
D)
I, II, and III
E)
None of the above gives the complete set of correct responses.
 

 5. 

Here's a quote from a medical journal: “An uncontrolled experiment in 17 women found a significantly improved mean clinical symptom score after treatment. Methodologic flaws make it difficult to interpret the results of this study.” The authors of this paper are skeptical about the significant improvement because
A)
there is no control group, so the improvement might be due to the placebo effect or to the fact that many medical conditions improve over time.
B)
the P-value given was P = 0.03, which is too large to be convincing.
C)
the response variable might not have an exactly Normal distribution in the population.
D)
the study didn’t use enough subjects to achieve any statistically significant findings.
E)
the mean is not resistant.
 

 6. 

A medical experiment compared the herb echinacea with a placebo for preventing colds. One response variable was “volume of nasal secretions” (if you have a cold, you blow your nose a lot). Take the average volume of nasal secretions in people without colds to be mc006-1.jpg = 1. An increase to mc006-2.jpg = 3 indicates a cold. The significance level of a test of mc006-3.jpg versus mc006-4.jpg is
A)
the probability that the test rejects mc006-5.jpg when mc006-6.jpg = 1 is true.
B)
the probability that the test rejects mc006-7.jpg when mc006-8.jpg = 3 is true.
C)
the probability that the test fails to reject mc006-9.jpg when mc006-10.jpg = 3 is true.
D)
the probability that the test fails to reject mc006-11.jpg when mc006-12.jpg = 1 is true.
E)
none of the above
 

 7. 

A radio show runs a phone-in survey each morning. One morning the show asked its listeners whether they would prefer Congress or the president to set policy for the nation. The majority of those phoning in their responses answered “Congress,” and the station reported the results as statistically significant. We may safely conclude that
A)
there is deep discontent in the nation with the president.
B)
it is unlikely that, if all Americans were asked their opinion, the result would differ from that obtained in the poll.
C)
there is strong evidence that the majority of Americans prefer Congress to set national policy.
D)
very few people other than the majority of those phoning in their responses prefer Congress to set policy for the nation.
E)
that the majority of Americans would actually prefer the president to set policy, because of the biased method of data collection.
 

 8. 

In a test of H0: µ = 100 against Ha: µ mc008-1.jpg 100, a sample of size 10 produces a sample mean of 103 and a P-value of 0.08. Thus, at the 0.05 level of significance
A)
there is sufficient evidence to conclude that µ mc008-2.jpg100.
B)
there is sufficient evidence to conclude that µ = 100.
C)
there is insufficient evidence to conclude that µ = 100.
D)
there is insufficient evidence to conclude that µ mc008-3.jpg100.
E)
there is sufficient evidence to conclude that µ = 103.
 

 9. 

Which of the following is not a condition for performing inference about a population mean mc009-1.jpg?
A)
Inference is based on n independent measurements.
B)
The population distribution is Normal or the sample size is large (say n > 30).
C)
To use a z test, we must know the population standard deviation mc009-2.jpg.
D)
The data are obtained from an SRS from the population of interest.
E)
Both np and n(1 – p) are 10 or greater.
 

 10. 

Resting pulse rate is an important measure of the fitness of a person's cardiovascular system, with a lower rate indicative of greater fitness. The mean pulse rate for all adult males is approximately 72 beats per minute. A random sample of 25 male students currently enrolled in the Faculty of Agriculture was selected and the mean resting pulse rate was found to be 80 beats per minute with a standard deviation of 20 beats per minute. The experimenter wishes to test if the students are less fit, on average, than the general population.

A possible Type II error here would be to
A)
conclude that the students are less fit (on average) than the general population when in fact they have equal fitness on average.
B)
conclude that the students have the same fitness (on average) as the general population when in fact they are less fit (on average).
C)
conclude that the students have the same fitness (on average) as the general population when in fact they have the same fitness (on average).
D)
conclude that the students are less fit (on average) than the general population, when, in fact, they are less fit (on average).
E)
conclude that the students have the same fitness (on average) when in fact they are more fit (on average).
 



 
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